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Kernel: Don't use IST on 32 bit target 

This only exists in 64 bit
This commit is contained in:
Bananymous 2025-07-18 19:10:48 +03:00
parent 7a054787ca
commit cceb066284
2 changed files with 7 additions and 1 deletions
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2
kernel/kernel/GDT.cpp
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@ -65,7 +65,9 @@ namespace Kernel
{
memset(&m_tss, 0x00, sizeof(TaskStateSegment));
m_tss.iopb = sizeof(TaskStateSegment);
#if ARCH(x86_64)
m_tss.ist1 = reinterpret_cast<vaddr_t>(g_boot_stack_top);
#endif
uintptr_t base = reinterpret_cast<uintptr_t>(&m_tss);

6
kernel/kernel/IDT.cpp
View File

@ -410,9 +410,11 @@ namespace Kernel
desc.offset1 = (uint16_t)((uintptr_t)handler >> 16);
#if ARCH(x86_64)
desc.offset2 = (uint32_t)((uintptr_t)handler >> 32);
desc.IST = ist;
#else
(void)ist;
#endif
desc.IST = ist;
desc.selector = 0x08;
desc.flags = 0x8E;
}
@ -454,8 +456,10 @@ namespace Kernel
ISR_LIST_X
#undef X
#if ARCH(x86_64)
idt->register_interrupt_handler(DoubleFault, isr8, 1);
static_assert(DoubleFault == 8);
#endif
#define X(num) idt->register_interrupt_handler(IRQ_VECTOR_BASE + num, irq ## num);
IRQ_LIST_X