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Kernel: Implement SpinLock without CriticalScope 

This actually is not even spinlock since it yields the current
thread. It will become one when I get to SMP though...
This commit is contained in:
Bananymous 2024-01-30 01:07:06 +02:00
parent cc79f55817
commit ca8e7b40bc
2 changed files with 5 additions and 18 deletions
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7
kernel/include/kernel/SpinLock.h
View File

@ -1,5 +1,6 @@
#pragma once
#include <BAN/Atomic.h>
#include <BAN/NoCopyMove.h>
#include <sys/types.h>
@ -19,7 +20,7 @@ namespace Kernel
bool is_locked() const;
private:
volatile pid_t m_locker = -1;
BAN::Atomic<pid_t> m_locker = -1;
};
class RecursiveSpinLock
@ -34,8 +35,8 @@ namespace Kernel
bool is_locked() const;
private:
pid_t m_locker = -1;
uint32_t m_lock_depth = 0;
BAN::Atomic<pid_t> m_locker = -1;
BAN::Atomic<uint32_t> m_lock_depth = 0;
SpinLock m_lock;
};

16
kernel/kernel/SpinLock.cpp
View File

@ -1,6 +1,5 @@
#include <kernel/Scheduler.h>
#include <kernel/SpinLock.h>
#include <kernel/CriticalScope.h>
namespace Kernel
{
@ -8,31 +7,18 @@ namespace Kernel
void SpinLock::lock()
{
pid_t tid = Scheduler::current_tid();
while (true)
{
{
CriticalScope _;
ASSERT(m_locker != tid);
if (m_locker == -1)
{
m_locker = tid;
break;
}
}
while (!m_locker.compare_exchange(-1, tid))
Scheduler::get().reschedule();
}
}
void SpinLock::unlock()
{
CriticalScope _;
ASSERT(m_locker == Scheduler::current_tid());
m_locker = -1;
}
bool SpinLock::is_locked() const
{
CriticalScope _;
return m_locker != -1;
}